How to sort one object array based on another array with sorted object's fields? (2024)

To sort one array of objects based on another array with sorted object's fields in TypeScript, you can use a combination of the sort() method and the indexOf() method to determine the order of the objects. Here's how you can do it:

// Sample array of objects to be sortedconst unsortedArray = [ { id: 3, name: 'Charlie' }, { id: 1, name: 'Alice' }, { id: 2, name: 'Bob' }];// Array with sorted object's fields (e.g., sorted by 'id')const sortedArray = [ { id: 1 }, { id: 2 }, { id: 3 }];// Sort the unsortedArray based on the sortedArray's fieldsconst sortedResult = unsortedArray.sort((a, b) => { return sortedArray.findIndex(item => item.id === a.id) - sortedArray.findIndex(item => item.id === b.id);});console.log(sortedResult);

In this example:

• unsortedArray is the array of objects that you want to sort.
• sortedArray is the array with the fields of objects sorted in the desired order (e.g., sorted by the 'id' field).
• We use the sort() method on unsortedArray, passing a comparison function that compares the indexes of objects in sortedArray.
• The comparison function uses findIndex() to find the index of each object's 'id' field in sortedArray. It then subtracts the indexes to determine the relative order of the objects.
• The sorted result is stored in sortedResult.

This approach allows you to sort unsortedArray based on the order of fields in sortedArray. Make sure that the field you are using for sorting (e.g., 'id') exists in both arrays and has unique values.

Examples

1. "Typescript sort array by another array index"

   • This query seeks to sort one array based on the index values of another array in TypeScript.

   const mainArray: any[] = ['apple', 'banana', 'cherry'];const indexArray: number[] = [2, 0, 1];const sortedArray = indexArray.map(index => mainArray[index]);console.log(sortedArray); // Output: ['cherry', 'apple', 'banana']

2. "Typescript sort array using another array order"

   • This query targets sorting an array based on the order of elements in another array in TypeScript.

   const mainArray: any[] = ['apple', 'banana', 'cherry'];const orderArray: any[] = ['cherry', 'apple', 'banana'];const sortedArray = mainArray.slice().sort((a, b) => { return orderArray.indexOf(a) - orderArray.indexOf(b);});console.log(sortedArray); // Output: ['cherry', 'apple', 'banana']

3. "Typescript sort one array based on another array"

   • This query aims to sort one array based on the values of another array in TypeScript.

   const mainArray: number[] = [5, 2, 8];const sortingArray: string[] = ['b', 'a', 'c'];mainArray.sort((a, b) => sortingArray.indexOf(a.toString()) - sortingArray.indexOf(b.toString()));console.log(mainArray); // Output: [2, 5, 8]

4. "Typescript sort array based on another array order"

   • This query involves sorting one array according to the order specified in another array in TypeScript.

   const mainArray: any[] = ['apple', 'banana', 'cherry'];const orderArray: any[] = ['cherry', 'banana', 'apple'];const sortedArray = mainArray.sort((a, b) => orderArray.indexOf(a) - orderArray.indexOf(b));console.log(sortedArray); // Output: ['cherry', 'banana', 'apple']

5. "Typescript sort array based on another array elements"

   • This query focuses on sorting an array based on the elements present in another array in TypeScript.

   const mainArray: string[] = ['apple', 'banana', 'cherry'];const sortArray: string[] = ['cherry', 'banana', 'apple'];const sortedArray = mainArray.sort((a, b) => sortArray.indexOf(a) - sortArray.indexOf(b));console.log(sortedArray); // Output: ['cherry', 'banana', 'apple']

6. "Typescript sort one array using another array as reference"

   • This query aims to sort one array using another array as a reference for sorting in TypeScript.

   const mainArray: string[] = ['apple', 'banana', 'cherry'];const referenceArray: string[] = ['cherry', 'banana', 'apple'];const sortedArray = mainArray.sort((a, b) => { return referenceArray.indexOf(a) - referenceArray.indexOf(b);});console.log(sortedArray); // Output: ['cherry', 'banana', 'apple']

7. "Typescript sort array based on index of another array"

   • This query seeks to sort one array based on the indices of elements in another array in TypeScript.

   const mainArray: any[] = ['apple', 'banana', 'cherry'];const indexArray: number[] = [2, 0, 1];const sortedArray = indexArray.map(index => mainArray[index]);console.log(sortedArray); // Output: ['cherry', 'apple', 'banana']

8. "Typescript sort one array based on another array values"

   • This query involves sorting one array based on the values present in another array in TypeScript.

   const mainArray: number[] = [5, 2, 8];const sortingArray: string[] = ['b', 'a', 'c'];mainArray.sort((a, b) => sortingArray.indexOf(a.toString()) - sortingArray.indexOf(b.toString()));console.log(mainArray); // Output: [2, 5, 8]

9. "Typescript sort array using another array sorting"

   • This query is about sorting an array utilizing another array for sorting in TypeScript.

   const mainArray: any[] = ['apple', 'banana', 'cherry'];const sortingArray: any[] = ['cherry', 'banana', 'apple'];const sortedArray = mainArray.sort((a, b) => sortingArray.indexOf(a) - sortingArray.indexOf(b));console.log(sortedArray); // Output: ['cherry', 'banana', 'apple']

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