sort array alphabetically swift 4 | Code Ease (2024)

Answered on: Sunday 12 May, 2024 / Duration: 19 min read

Programming Language: Swift , Popularity :8/10


sort array alphabetically swift 4 | Code Ease (1)

Solution 1:

To sort an array alphabetically in Swift 4, you can use the sorted() method or the sort(by:) method. Here is an example using both methods:

swift
// Define an array of strings
var fruits = ["apple", "orange", "banana", "kiwi"]
// Using sorted() method
let sortedFruits1 = fruits.sorted()
print(sortedFruits1) // Output: ["apple", "banana", "kiwi", "orange"]
// Using sort(by:) method
let sortedFruits2 = fruits.sorted(by: { $0 < $1 })
print(sortedFruits2) // Output: ["apple", "banana", "kiwi", "orange"]

In the above code, we have an array of fruits that we want to sort alphabetically. We use the sorted() method to create a new sorted array and print the result. We also use the sort(by:) method with a closure that compares two elements and returns true if the first element should be ordered before the second element.

Both methods will give the same output, which is the sorted array of fruits in alphabetical order.

Solution 2:

Sorting an Array Alphabetically in Swift 4

Swift provides a simple and efficient way to sort an array of strings alphabetically. The sort() method on arrays arranges the elements in ascending order, which means alphabetically for strings.

Code Example:

swift
var names = ["Alice", "Bob", "Carol", "Dave", "Eve"]
names.sort()
print(names)

Output:


["Alice", "Bob", "Carol", "Dave", "Eve"]

How it Works:

The sort() method rearranges the elements in place, meaning it modifies the original array. It uses a sorting algorithm called quicksort, which is known for its average-case time complexity of O(n log n), where n is the number of elements in the array.

Custom Sorting:

You can also provide a custom sorting closure to the sort() method to define your own sorting criteria. For example, to sort the names in descending order:

swift
var names = ["Alice", "Bob", "Carol", "Dave", "Eve"]
names.sort(by: >)
print(names)

Output:


["Eve", "Dave", "Carol", "Bob", "Alice"]

In this case, the > closure compares two elements and returns true if the first element should come after the second in the sorted order.

Additional Notes:

* The sort() method preserves the type of the array elements. If the array contains different types of objects, it will sort them based on their natural ordering.
* You can also use the sorted() method to create a new sorted array without modifying the original one.
* For large arrays, you can use the sorted(by:) method with a custom sorting closure that optimizes the performance for your specific use case.

Solution 3:

Sure, to sort an array alphabetically in Swift 4, you can use the sorted(by:) function. This function takes a closure as an argument that defines the sorting criteria. In the case of sorting alphabetically, you can use the localizedStandardCompare method to compare two strings.

Here's an example:

swift
var names: [String] = ["John", "Alice", "Bob", "Charlie"]
names = names.sorted(by: { (name1: String, name2: String) -> Bool in
return name1.localizedStandardCompare(name2) == .orderedAscending
})
print(names)

Output:

swift
["Alice", "Bob", "Charlie", "John"]

In the above code, we first define an array of strings names. We then use the sorted(by:) function to sort the array. The closure takes two parameters name1 and name2 of type String. We use the localizedStandardCompare method to compare the two strings. If name1 is less than name2, localizedStandardCompare returns .orderedAscending, and we return true to indicate that name1 should come before name2. If name1 is greater than or equal to name2, we return false to indicate that name1 should come after or at the same position as name2.

Note that localizedStandardCompare performs a locale-sensitive comparison, taking into account language and cultural differences that might affect string comparison.

You can also use the sort() function to sort the array in place:

swift
var names: [String] = ["John", "Alice", "Bob", "Charlie"]
names.sort(by: { (name1: String, name2: String) -> Bool in
return name1.localizedStandardCompare(name2) == .orderedAscending
})
print(names)

Output:

swift
["Alice", "Bob", "Charlie", "John"]

In this example, we use the sort() function instead of sorted(by:) to sort the array in place. The behavior is the same as before.

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sort array alphabetically swift 4 | Code Ease (2024)
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